After dividing moles by the smallest mole value, you may see ratios with decimal remainders. This table shows the exact multiplier to apply to convert them to whole numbers. This calculator applies these automatically.
| Ratio Decimal | Multiply All By | Fraction It Represents | Example |
|---|---|---|---|
| .5 | ×2 | 1/2 | 1.5 and 1.0 become 3 and 2 |
| .33 or .67 | ×3 | 1/3 or 2/3 | 1.33 and 1.0 become 4 and 3 |
| .25 or .75 | ×4 | 1/4 or 3/4 | 1.25 and 1.0 become 5 and 4 |
| .2, .4, .6, or .8 | ×5 | 1/5 through 4/5 | 1.4 and 1.0 become 7 and 5 |
| .167 or .833 | ×6 | 1/6 or 5/6 | 1.167 and 1.0 become 7 and 6 |
| .143 or .857 | ×7 | 1/7 or 6/7 | 1.143 and 1.0 become 8 and 7 |
The Complete Guide to Finding the Empirical Formula
Finding an empirical formula is one of the most fundamental skills in general chemistry. Whether you are working from lab data on a new compound or studying for the AP Chemistry exam, the four-step process below is universal. This calculator automates every step - but understanding the math underneath is what makes the difference on a test.
How to Use This Calculator
Select your input mode at the top: "Mass (%)" if you have percent composition data, or "Mass (g)" if you have direct gram measurements. Add one row per element by entering the element symbol (e.g., C, H, O, N, Fe) and its corresponding value. The formula and step-by-step table update instantly with every keystroke - no button to press.
In percentage mode, the calculator warns you if your values do not sum within 1% of 100%, which catches common data-entry errors. You can use up to any number of elements - just click "Add Element" for each additional one.
The Four Steps - Explained
STEP 1Convert to Grams. If you have percent composition, assume a 100-gram sample. This converts every percentage directly to grams (34% oxygen = 34 grams oxygen). If you already have grams, skip this step.
STEP 2Convert Grams to Moles. Divide each element's gram amount by its molar mass (atomic weight). This gives you raw mole counts for each element. The mole values at this stage are not yet a clean ratio.
STEP 3Divide by the Smallest Mole Value. Find the element with the fewest moles, then divide all mole counts by that number. The element with the smallest value becomes 1.00. This produces the initial ratio. If all ratios are already whole numbers (or within 0.05 of one), you are done.
STEP 4Apply a Multiplier if Needed. If any ratio contains a recognizable fraction (.5, .33, .25, .2), multiply all ratios by the appropriate integer to clear the decimals. See the cheat sheet above for the correct multiplier for each fraction. The resulting integers are the subscripts in the empirical formula.
Worked Example: Ethylene (C2H4)
Suppose a compound contains 85.63% carbon and 14.37% hydrogen. Assume 100 g: 85.63 g C and 14.37 g H. Divide by atomic masses: 85.63 / 12.011 = 7.130 mol C, and 14.37 / 1.008 = 14.256 mol H. Divide both by 7.130 (the smaller): C = 1.00, H = 2.000. Both are whole numbers, so the empirical formula is CH2. (The molecular formula, found separately using molar mass data, happens to be C2H4.)